OK, this seems to do the trick, but boy is it a lot of code. Anythong more
pythonic?
>>> l = list(d.items())
>>> l
[('squib', '007')]
>>> l[0]
('squib', '007')
>>> l[0][0]
'squib'
>>>
On 03/18/2016 05:33 PM, Fillmore wrote:
I must be missing something simple, but...
Python 3.4.0 (default, Apr 11 2014, 13:05:11)
[GCC 4.8.2] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> d = dict()
>>> d['squib'] = "007"
>>> # I forget that 'squib' is my key to retrieve the only element in d
...
>>> type(d.items())
<class 'dict_items'>
>>> key = d.items()[0]
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: 'dict_items' object does not support indexing
>>> key,_ = d.items()
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
ValueError: need more than 1 value to unpack
>>> key,b = d.items()
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
ValueError: need more than 1 value to unpack
>>> print(d.items())
dict_items([('squib', '007')])
>>> print(d.items()[0])
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: 'dict_items' object does not support indexing
>>>
what am I missing? I don't want to iterate over the dictionary.
I know that there's only one element and I need to retrieve the key
thanks
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