Maurice <mauricioliveiragua...@gmail.com> writes:
> Hello, hope everything is okay. I think someone might have dealt with
> a similar issue I'm having.
>
> Basically I wanna do the following:
>
> I have a list such [6,19,19,21,21,21] (FYI this is the item of a
>certain key in the dictionary)
>
> And I need to convert it to a list of 32 elements (meaning days of the
> month however first element ie index 0 or day zero has no meaning -
> keeping like that for simplicity's sake).
> Therefore the resulting list should be:
> [0,0,0,0,0,0,1,0,0,0...,2,0,3,0...0]
How about
reduce(lambda counts, day: counts[:day] + [counts[day]+1] + counts[day+1:],
days, [0]*32)
? (reduce is in functools).
Not efficient, but sometimes you just want to the job done.
More efficient would be:
def inc_day(counts, day): counts[day] += 1; return counts
reduce(inc_day, days, [0]*32)
For experts here: why can't I write a lambda that has a statement in it
(actually I wanted two: lambda l, i: l[i] += 1; return l)?
<snip>
--
Ben.
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