On Sunday, April 3, 2016 at 8:41:49 PM UTC+5:30, BartC wrote:
> On 03/04/2016 15:41, Loop.IO wrote:
> > On Sunday, April 3, 2016 at 1:12:23 AM UTC+1, BartC wrote:
> >> On 02/04/2016 23:31, Loop.IO wrote:
> >>
> >>> Oh i see, so the code prompts for a name.. so i'm more lost than i
> >>> thought, what do I need to change to make it just create the file with
> >>> the chosen name Launch2.bat without the prompt?
> >>
> >> If you don't want the user to enter anything, then I explained how
> >> before, just use:
> >>
> >> name='C:\\Documents\\PythonCoding\\launch2.bat'
> >>
> >> if that's the file name you need.
> >>
> >> --
> >> Bartc
> >
> > Hi Bartc, i tried that, didn't work
>
> You mean it gave an error when you tried to create that file?
>
> Does that path already exist on your machine? If not then trying to
> create a file in a non-existent path won't work.
>
> You can create the path manually outside of Python. Or look up the docs
> to find out how to do that. A quick google suggested using os.makedirs
> (to create multiple nested paths at the same time).
>
> The following code worked on my machine:
>
> import sys
> import os
>
> def create():
> print("creating new file")
>
> path="c:/Documents/PythonCoding/"
> name=path+"launch2.bat"
>
> try:
> os.stat(path)
> except:
> os.makedirs(path)
>
> print (name)
>
> try:
> file=open(name,'w')
> file.close()
> except:
If you dont want the vigilantes out in their squadrons please dont do it that
way.
More seriously you can do what you like but dont teach beginners to use bare
excepts.
Do
except IOError # I think... else whatever is the error you want to trap
--
https://mail.python.org/mailman/listinfo/python-list
