ast wrote: > > <martin.spic...@gmail.com> a écrit dans le message de > news:52f7516c-8601-4252-ab16-bc30c59c8...@googlegroups.com... >> Hi, >> >> there may be a serious error in python's int() function: >> >> print int(float(2.8/0.1)) >> >> yields >> >> 27 >> >> instead of 28!! >> >> I am using Python Python 2.7.6, GCC 4.8.2 on Linux Ubuntu. >> >> Is that known? >> Best, >> Martin > > > I have a similar question, so I post my message here. > Hope this will not annoy the OP
Well, you "annoy" me ;) Would you please always take the time to come up with a subject line that matches your question. You should also start a new thread. > Is it sure that the square root of a square number is always > an integer ? > > I would not like to get a result as 345.99999999 > > from math import sqrt > >>>>sqrt(16) > 4.0 >>>> sqrt(16).is_integer() > True > >>>> for n in range(1000000): > ... if not sqrt(n**2).is_integer(): > ... print(sqrt(n**2)) > > it seems to work ... but does it work for all integers ? Even if you get an integer it may not be the one you are expecting: >>> sqrt((10**22)**2) == 10**22 True >>> sqrt((10**23)**2) == 10**23 False >>> sqrt((10**23)**2).is_integer() True >>> int(sqrt((10**23)**2)) 99999999999999991611392 -- https://mail.python.org/mailman/listinfo/python-list
