i got M1 to M5 and V6 operator
and would like to do a full combination and result will also act among each
other,
map reduce attract my application
how to use this in this example?
actually below is like vlookup
then example is op3(op2(op1(x->y, y->z)), x->z)
search which combinations will result in a column result is 1
M1 = {}
M2 = {}
M3 = {}
M4 = {}
M5 = {}
V6 = {}
M1['00']=0
M1['01']=1
M1['02']=1
M1['10']=1
M1['11']=1
M1['12']=1
M1['20']=1
M1['21']=1
M1['22']=1
M2['00']=0
M2['01']=0
M2['02']=1
M2['10']=0
M2['11']=1
M2['12']=1
M2['20']=1
M2['21']=1
M2['22']=1
M3['00']=0
M3['01']=0
M3['02']=0
M3['10']=0
M3['11']=1
M3['12']=1
M3['20']=0
M3['21']=1
M3['22']=1
M4['00']=0
M4['01']=1
M4['02']=0
M4['10']=1
M4['11']=1
M4['12']=1
M4['20']=0
M4['21']=1
M4['22']=1
M5['00']=0
M5['01']=0
M5['02']=0
M5['10']=0
M5['11']=1
M5['12']=1
M5['20']=0
M5['21']=1
M5['22']=1
V6['00']=1
V6['01']=1
V6['02']=1
V6['10']=1
V6['11']=1
V6['12']=1
V6['20']=0
V6['21']=1
V6['22']=1
MM = {}
MM[0] = M1
MM[1] = M2
MM[2] = M3
MM[3] = M4
MM[4] = M5
MM[5] = V6
m = 3
b = [str(i)+str(j)+str(k) for i in range(m) for j in range(m) for k in range(m)]
b[21][0:1]+b[21][1:2]
b[21][1:2]+b[21][2:3]
b[21][0:1]+b[21][2:3]
#def node(mmm, A):
#H2 = [MM[mmm][b[i][0:1]+b[i][1:2]] for i in range(len(b))]
#return H2
#node(5, b[i][0:1]+b[i][1:2])
H2 = [MM[5][b[i][0:1]+b[i][1:2]] for i in range(len(b))]
H3 = [MM[5][b[i][0:1]+b[i][1:2]] for i in range(len(b))]
[str(k)+str(v) for k, v in zip(H2, H3)]
import itertools
deep = 3
finalresult = []
def DFS(H2, H3, b, deep, mresult)
mylist = [i for i in range(0,7-1)]
for aa,bb in itertools.combinations(mylist, 2):
print(aa,bb)
if deep == 3:
#op0, op1
op1xy = [MM[aa][b[i][0:1]+b[i][1:2]] for i in range(len(b))]
op1yz = [MM[aa][b[i][1:2]+b[i][2:3]] for i in range(len(b))]
op1xz = [MM[aa][b[i][0:1]+b[i][2:3]] for i in range(len(b))]
op2xy = [MM[bb][b[i][0:1]+b[i][1:2]] for i in range(len(b))]
op2yz = [MM[bb][b[i][1:2]+b[i][2:3]] for i in range(len(b))]
op2xz = [MM[bb][b[i][0:1]+b[i][2:3]] for i in range(len(b))]
mresult.append(op1xy)
mresult.append(op1yz)
mresult.append(op1xz)
mresult.append(op2xy)
mresult.append(op2yz)
mresult.append(op2xz)
else:
H1 = H2
H9 = H3
ba = b
b = [str(k)+str(v) for k, v in zip(H2, H3)]
DFS(H1, H9, b)
b = ba
DFS(0, 0, 0, 3, finalresult)
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