On Tue, Sep 6, 2016 at 2:29 AM, Smith <sm...@smith.it> wrote:
>> What exactly are you expecting the 'break' to do here? Can you explain
>> to me the intent of your code?
>>
>> ChrisA
>>
> I'd like to create a script that searches the directory .py files.
> If the script does not find the file extension .py would return the error
> message "File Not Found".
Okay. So the logic needs to be like this:
For every file in this directory:
If the file has the extension ".py":
Print out the file name
If we didn't print out any file names:
Print out "File not found"
Notice how this pseudo-code is extremely close to actual Python code.
Here's a revision of your code that does more-or-less that. (I'm
keeping your original prompt; Python 3 is quite happy to work with all
human languages equally, and not just as text strings - you can name
your variables in Italian, too.)
a = input("Digita la directory dove vuoi trovare i file py: ")
found_any = False
for file in os.listdir(a):
if file.endswith(".py"):
print(file)
found_any = True
if not found_any:
print("File not found")
There's no "else" clause, because the algorithm doesn't care about
non-py files; it cares only whether or not any .py files were found.
Does that help you understand what's going on? I can elaborate more if you like.
ChrisA
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