Anuradha Laxminarayan wrote:
seq f g h = f (\s1 -> g h s1)better be written as seq f g x = f (\s1 -> g x s1) because naming conventions imply that h is function.
Well, for the subset of monads I'm talking about, it always is a function -- it's the continuation to be run after f and g. -- Greg -- https://mail.python.org/mailman/listinfo/python-list
