On 30/12/2016 21:20, Deborah Swanson wrote:
I've already learned one neat trick to collapse a conditional:a = expression1 if condition else expression2 Here I have a real mess, in my opinion: if len(l1[st]) == 0: if len(l2[st]) > 0: l1[st] = l2[st] elif len(l2[st]) == 0: if len(l1[st]) > 0: l2[st] = l1[st]
This doesn't make sense. The main block is executed when len(l1[st]) is 0, but you're testing for len(l1[st])>0 in the last if statement (which can't see the assignment to l1[st], so can never be true).
Try writing it out on paper using A and B instead l1[st] and l2[st] as they look confusing.
You might also be evaluating len(l2[st]) twice. -- Bartc -- https://mail.python.org/mailman/listinfo/python-list
