On Tuesday, October 17, 2017 at 5:01:13 PM UTC-5, Peter Otten wrote: > Daniel Flick wrote: > > > On Tuesday, October 17, 2017 at 4:25:02 PM UTC-5, Daniel Flick wrote: > >> <SNIP> > >> Peter, I am not following. Are you saying that there is a function that > >> returns the network only? network_address was giving me the mask > >> attached to the end but maybe I was doing something wrong. > >> > >> For an input of LAN_IP=192.168.99.1/24 > >> ipaddress.IPv4Interface(LAN_IP).ip > >> returns 192.168.99.0/24 > >> > >> I need the 192.168.99.0 part only. > > > > OOPS! I meant > > For an input of LAN_IP=192.168.99.1/24 > > ipaddress.IPv4Interface(LAN_IP).network > > returns 192.168.99.0/24 > > In the body of your post you had 192.168.1.128/25, so I mistook > 192.168.1.129/25 as a typo. However, once you have > > >>> import ipaddress > >>> ipaddress.ip_interface("192.168.99.1/24").network > IPv4Network('192.168.99.0/24') > > you can simply add the step from my first answer: > > >>> ipaddress.ip_interface("192.168.99.1/24").network.network_address > IPv4Address('192.168.99.0') > > Unless I'm misunderstanding again...
That seems to be spot on. I will try that. I used the /25 to illustrate that that the network may not end in zero. I had asked this question in the Mako forum and I had a few answers to drop the last octet and add zero which was not correct. Thanks for your help! -- https://mail.python.org/mailman/listinfo/python-list