> On Oct 19, 2017, at 10:02 AM, Stefan Ram <r...@zedat.fu-berlin.de> wrote: > > Israel Brewster <isr...@ravnalaska.net> writes: >> t10 = {'daily': 0, 'WTD': 0, 'MTD': 0, 'YTD': 0,} >> increment the appropriate bin counts using a bunch of if statements. > > I can't really completely comprehend your requirements > specification, you might have perfectly described it all and > it's just too complicated for me to comprehend, but I just > would like to add that there are several ways to implement a > "two-dimensional" matrix. You can also imagine your > dictionary like this: > > example = > { 'd10': 0, 'd15': 0, 'd20': 0, 'd215': 0, > 'w10': 0, 'w15': 0, 'w20': 0, 'w215': 0, > 'm10': 0, 'm15': 0, 'm20': 0, 'm215': 0, > 'y10': 0, 'y15': 0, 'y20': 0, 'y215': 0 } > > Then, when the categories are already in two variables, say, > »a« (»d«, »w«, »m«, or »y«) and »b« (»10«, »15«, »20«, or > »215«), you can address the appropriate bin as
Oh, I probably was a bit weak on the explanation somewhere. I'm still wrapping *my* head around some of the details. That's what makes it fun :-) If it helps, my data would look something like this: [ (date, key, t1, t2), (date, key, t1, t2) . . ] Where the date and the key are what is used to determine what "on-time" is for the record, and thus which "late" bin to put it in. So if the date of the first record was today, t1 was on-time, and t2 was 5 minutes late, then I would need to increment ALL of the following (using your data structure from above): d10, w10, m10, y10, d25, w25, m25 AND y25 Since this record counts not just for the current day, but also for week-to-date, month-to-date and year-to-date. Basically, as the time categories get larger, the percentage of the total records included in that date group also gets larger. The year-to-date group will include all records, grouped by lateness, the daily group will only include todays records. Maybe that will help clear things up. Or not. :-) > > example[ a + b ]+= 1 Not quite following the logic here. Sorry. > > . (And to not have to initialized the entries to zero, > class collections.defaultdict might come in handy.) Yep, those are handy in many places. Thanks for the suggestion. ----------------------------------------------- Israel Brewster Systems Analyst II Ravn Alaska 5245 Airport Industrial Rd Fairbanks, AK 99709 (907) 450-7293 ----------------------------------------------- > > -- > https://mail.python.org/mailman/listinfo/python-list -- https://mail.python.org/mailman/listinfo/python-list