Perhaps: import lzma lzc = lzma.LZMACompressor() out1 = lzc.compress(b"Some data\n") out2 = lzc.compress(b"Another piece of data\n") out3 = lzc.compress(b"Even more data\n") out4 = lzc.flush() # Concatenate all the partial results: result = b"".join([out1, out2, out3, out4])
? lzma compresses harder than bzip2, but it's probably slower too. On Fri, Feb 9, 2018 at 5:36 PM, Steven D'Aprano <steve+comp.lang.pyt...@pearwood.info> wrote: > I want to compress a sequence of bytes one byte at a time. (I am already > processing the bytes one byte at a time, for other reasons.) I don't > particularly care *which* compression method is used, and in fact I'm not > even interested in the compressed data itself, only its length. So I'm > looking for something similar to this: > > count = 0 > for b in stream: > process(b) > count += incremental_compressor.compressor(b) > > > > or some variation. Apart from bzip2, do I have any other options in the > std lib? > > https://docs.python.org/3/library/bz2.html#incremental-de-compression > > > > -- > Steve > > -- > https://mail.python.org/mailman/listinfo/python-list -- https://mail.python.org/mailman/listinfo/python-list
