On Sunday, May 20, 2018 at 6:56:05 PM UTC-4, Ben Bacarisse wrote:
> "Michael F. Stemper" <michael.stem...@gmail.com> writes:
>
> > On 2018-05-20 16:19, Ben Bacarisse wrote:
> >> bruceg113...@gmail.com writes:
> >>
> >>> Lets say I have the following tuple like string.
> >>> (128, 020, 008, 255)
> >>>
> >>> What is the best way to to remove leading zeroes and end up with the
> >>> following.
> >>> (128, 20, 8, 255) -- I do not care about spaces
> >>
> >> You could use a regexp:
> >>
> >> import re
> >> ...
> >> re.sub(r"(?<![0-9])0+(?=[0-9])", "", "(128, 020, 008, 255)")
> >>
> >> I post this because I think it works (interesting corner cases are 10005
> >> and 000),
> >
> > Seeing this makes me realize that mine will eliminate any numbers that
> > are all leading zero, including '0'. Also, forms like '-0042' will be
> > left unchanged.
>
> I realised after posting the negatives won't work. Not, I suspect, an
> issue for the OP but -0042 can certainly be said to have "leading
> zeros".
>
> > Maybe splitting it into integer forms and sending each through
> > str( int( ) ) would be the safest.
>
> Yup. I gave a version of that method too which handles negative numbers
> by accident (by leaving the - in place!). A better version would be
>
> re.sub(r"-?[0-9]+", lambda m: str(int(m.group(0))), s)
>
> <snip>
> --
> Ben.
Looking over the responses, I modified my original code as follows:
>>> s = "(0000128, 020, 008, 255, -1203,01,-000, -0123)"
>>> ",".join([str(int(i)) for i in s[1:-1].split(",")])
'128,20,8,255,-1203,1,0,-123'
If I decide I need the parentheses, this works.
>>> "(" + ",".join([str(int(i)) for i in s[1:-1].split(",")]) + ")"
'(128,20,8,255,-1203,1,0,-123)'
Thanks,
Bruce
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