On Fri, Jun 01, 2018 at 08:02:27AM -0700, Mike McClain wrote: > On Thu, May 31, 2018 at 07:44:35PM -0700, Mike McClain wrote: > <snip> > > Is there a way in a script to know which version of python is being > > run so I can write: > > If (version == 2.7): > > do it this way > > elsif (version == 3.2): > > do it another way > > > > Thanks for the responses,
Those responses were sys.version_info.major and the module 'six'. The first works here: if( sys.version_info.major == 3 ): choice = input("<CR> to continue, or <ESC> to abort") else: choice = raw_input("<CR> to continue, or <ESC> to abort") # OK in 2.7 but not here: if( sys.version_info.major == 3 ): print( row, sep=', ') else: print ', '.join(row) # failing in 3.2 Both of the above print statements throw syntax errors, one under 2.7 the other under 3.2. I looked at 'six' and it putting wrappers around calls would mean a rewrite of what is basically just a playground for exploring what python is and certainly not worth the trouble to rewrite much. It looks like what I was wanting is something like 'C's #if, a compiler conditional. Does python have anything like that to tell the interpreter to ignore a line that is not a comment or a quoted string? Thanks, Mike -- The depression won't end till we grow a generation that knows how to live on what they got. - Will Rogers -- https://mail.python.org/mailman/listinfo/python-list