billiejoex wrote: > Hi all. I'd need to aproximate a given float number into the next (int) > bigger one. Because of my bad english I try to explain it with some > example: > > 5.7 --> 6 > 52.987 --> 53 > 3.34 --> 4 > 2.1 --> 3
What about 2.0? By your spec that should be rounded to 3 - is that what you
intend?
If you do, you can simply do this:
def approx(x):
return int(x+1.0)
Regards,
Michael.
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