[EMAIL PROTECTED] wrote:
> update works like append for lists
>
> a = {}
> a['a']='a'
> a['c']='c'
> b={}
> b['b'] = 'b'
> c={}
> c.update(a)
> c.update(b)
>
So what do you think is the better way to do it, based on speed or
aesthetics?
(1)
c=a.copy()
c.update(b)
or
(2)
c={}
c.update(a)
c.update(b)
Iain
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