On Wednesday, September 26, 2018 at 12:50:20 AM UTC-7, vito.d...@gmail.com
wrote:
> I have "abused" the "else" clause of the loops to makes a break "broke" more
> loops
I did this once upon a time. In recent years, when I start writing tricky
nested loops, I frequently find myself reaching for itertools.product() to
flatten the loops instead.
This code accomplishes the same task as yours. I'll leave it to you to decide
whether you prefer it. There are things that I dislike about it, but the flow
control part is clear.
from itertools import product
msgs = ("i: {}", "\tj: {}", "\t\tk: {}")
old = 3*[None]
for new in product(range(10), repeat=3):
for n, (msg, changed) in enumerate(zip(msgs, [x!=y for x, y in zip(old,
new)])):
if changed:
print(msg.format(new[n]))
if condition(*new): # your condition() took three separate arguments
break
old = new
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