fld = [ ] data = shlex.split(ln) for item in data: fld.append(item) fld = fld + [0] * (5 - len(data))
On Sat, 29 Sep 2018 at 11:03, Glen D souza <glenpo...@gmail.com> wrote: > i have a approach, it may not be best > > fld = [ ] > for data in shlex.split(ln): > fld.append(data) > > > > On Sat, 29 Sep 2018 at 07:52, <jlada...@itu.edu> wrote: > >> On Friday, September 28, 2018 at 11:03:17 AM UTC-7, Chris Green wrote: >> > I have a list created by:- >> > >> > fld = shlex.split(ln) >> > >> > It may contain 3, 4 or 5 entries according to data read into ln. >> > What's the neatest way of setting the fourth and fifth entries to an >> > empty string if they don't (yet) exist? Using 'if len(fld) < 4:' feels >> > clumsy somehow. >> >> How about this? >> >> from itertools import chain, repeat >> temp = shlex.split(ln) >> fld = list(chain(temp, repeat("", 5-len(temp)))) >> -- >> https://mail.python.org/mailman/listinfo/python-list >> > -- https://mail.python.org/mailman/listinfo/python-list