On Mon, 2018-10-01 at 10:49 -0700, [email protected] wrote:
> I have a string like this:
>
> b'\tC:94.3%[S:89.9%,D:4.4%],F:1.7%,M:4.0%,n:1440\n'
>
> And I would like to extract the numbers corresponding to S,D,F and M in this
> string and convert them into an array like this:
>
> [ '89.9', '4.4', '1.7', '4.0']
>
> Any help would be appreciated!
Hi there,
import re
s = b'\tC:94.3%[S:89.9%,D:4.4%],F:1.7%,M:4.0%,n:1440\n'
pattern = re.compile('S:([0-9.]+)%,D:([0-9.]+)%\],F:([0-9.]+)%,M:([0-9.]+)')
stuff = [x for x in re.findall(pattern, s)[0]]
You may consider just getting everthing out of your string and then munging it
to what ever you like.
I mean:
pattern = re.compile('([A-Za-z]):([0-9.]+)')
{x: float(y) for x, y in re.findall(pattern, s)
Then you could read what ever and put it in a handy format wherein it is clear
what it was. I mean:
stuff = []
for s in iostream:
stuff.append({x: float(y) for x, y in re.findall(pattern, s)})
HTH
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