On 2019-01-08 00:47, i...@koeln.ccc.de wrote:
You might do something like
if len(a) == 0 or all(i == a[0] for i in a[1:]):
You don't need to check the length of the list because if the list is
empty, 'all' will return True anyway.
This should be linear complexity and short circuiting and in general it
doesn't get much better than this. Though I wouldn't bet there isn't a
better (faster/clearer/more readable) solution.
On Mon, Jan 07, 2019 at 05:14:14PM -0700, Bob van der Poel wrote:
I need to see if all the items in my list are the same. I was using set()
for this, but that doesn't work if items are themselves lists. So, assuming
that a is a list of some things, the best I've been able to come up with it:
if a.count( targ ) == len(a):
I'm somewhat afraid that this won't scale all that well. Am I missing
something?
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