On 1/8/19 9:20 AM, Alister wrote:
On Tue, 08 Jan 2019 17:15:17 +0000, Alister wrote:
On Tue, 08 Jan 2019 16:48:58 +0200, Serhiy Storchaka wrote:
08.01.19 11:07, Peter Otten пише:
Bob van der Poel wrote:
I need to see if all the items in my list are the same. I was using
set()
for this, but that doesn't work if items are themselves lists. So,
assuming that a is a list of some things, the best I've been able to
come up with it:
if a.count( targ ) == len(a):
I'm somewhat afraid that this won't scale all that well. Am I missing
something?
a[1:] == a[:-1]
:)
Very clever! It is definitely the shortest solution.
would that still not return true if the list was a palindrome?
ignore me, just tried & ok
You were right the first time. The above comparison should have been
a == a[::-1]
A palindrome will pass.
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