On 11/04/20 12:19 am, Pieter van Oostrum wrote:
Your Pardon is not a class, it is a function.
To elaborate on that a bit, the way inheritance of metaclasses works is that when you define a class, if you don't explicity specify a metaclass, it uses the class of the base class as the metaclass. Usually when you specify a metaclass, you use an actual class. But your "metaclass" is a function that returns an instance of class "type". So the class of your base class ends up being "type", which is no different from what it would have been if you didn't specify a metaclass.
I find it peculiar that you can give a function as metaclass.
Yes, it just calls whatever object you give it, which allows for various fun things. You'd be risking a lynching if you took advantage of it for anything important, though.:-) -- Greg -- https://mail.python.org/mailman/listinfo/python-list
