ast wrote at 2020-5-4 15:20 +0200: >doctest of the sample function funct() doesn't works >because flag used by funct() is the one defined in >first line "flag = True" and not the one in the >doctest code ">>> flag = False". > >Any work around known ? > > >flag = True # <- funct() always use this one > >def funct(): > """ > Code for doctest: > > >>> flag = True > >>> funct() > 'Yes' > >>> flag = False # <- Ignored unfortunalely > >>> funct() > 'No' > """ > > if flag: > return "Yes" > else: > return "No" > >if __name__ == "__main__": > import doctest > doctest.testmod() > > > >Failed example: > funct() >Expected: > 'No' >Got: > 'Yes' >********************************************************************** >1 items had failures: > 1 of 4 in __main__.funct >***Test Failed*** 1 failures.
The "flag" used inside "funct" refers to the definition in "funct.__globals__" (i.e. the module where "funct" is defined in). As your observation shows, this is not the "flag" changed by the doctest. The doctest behavior reflects the use in a function or a foreign module (rather than a use at the top level of the module defining "funct"). -- https://mail.python.org/mailman/listinfo/python-list
