On 2020-12-12, dn <pythonl...@danceswithmice.info> wrote: > On 12/12/2020 14:25, Bischoop wrote: >> >> >> >> I've function asking question and comparing it, if is not matching 'yes' >> it does call itself to ask question again. The problem is that when >> function is called second time it returns old value or with additional >> else statement it returns none. >> >> Code: https://bpa.st/KVGA >> >> How this functions should look properly? > > > In the event of "yes" the function returns a value (return ask). > When the function calls itself, what happens to the return-ed value?
Well I've put the output in a paste as well, anyway here is what is in a
paste:
def question():
ask = input("Are you OK?:").lower()
if ask != 'yes':
question()
return ask
print (question())
#output:
Are you OK?:no
Are you OK?:no
Are you OK?:yes
no
---------------------------------------
#Another way with 'elif' statment returns none
def question():
ask = input("Are you OK?:").lower()
if ask != 'yes':
question()
elif ask == 'yes':
return ask
print (question())
#output:
Are you OK?:no
Are you OK?:yes
None
#Tried also nested
functions, same results:
def question():
ask = input("Are you
OK?:").lower()
def
check_question(n):
if ask
!=
'yes':
question()
else:
return
ask
m
=
check_question(ask)
print
(m)
question()
#output:
Are
you
OK?:no
Are
you
OK?:yes
None
Process
finished
with
exit
code
0
--
https://mail.python.org/mailman/listinfo/python-list
