On 2021-01-14, Stefan Ram <r...@zedat.fu-berlin.de> wrote: > > If you want to know why, maybe you should insert print > statements to see the values of critical variables and > expression, especially in loops. > > Then compare the printed values with your expectations. > > Also, decompose into meaningful functions and test each > function separately. > >
I sat to it again and solved it. import timeit run1 = ''' s = 'aabskaaaabadcccc' lil = tuple(set(s)) # list of characters in s li=[0,0,0,0,0,0] # list for counted repeats for i in lil: c = 0 h= lil.index(i) for letter in s: if letter == i: c += 1 if c > li[lil.index(letter)]: li[lil.index(letter)] = c else: c=0 continue m = max(li) for index, j in enumerate(li): if li[index] == m: print(f'{lil[index]} appears {m} consecutive times') ''' print(timeit.timeit(stmt=run1, number=1)) output: c appears 4 consecutive times a appears 4 consecutive times 0.00013008200039621443 -- https://mail.python.org/mailman/listinfo/python-list