On 2021-05-12 15:48, Michael F. Stemper wrote:
On 12/05/2021 08.26, Dino wrote:
Hi, here's my (probably unusual) problem. Can a Python (3.7+) script
access its own source code?
Here is a fairly simple python program that reads itself:
================================================
#!/usr/bin/python
import sys
with open( sys.argv[0], "rt" ) as myself:
for line in myself:
junk = sys.stdout.write( "%s" % (line) )
sys.exit(0)
================================================
It's not bullet-proof. If you put it in a directory in your $PATH and
run it from somewhere else, it won't work.
How about this:
with open(__file__) as myself:
print(myself.read(), end='')
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