Le 05/08/2021 à 17:11, ast a écrit :
Le 05/08/2021 à 11:40, Jach Feng a écrit :
I want to distinguish between numbers with/without a dot attached:
text = 'ch 1. is\nch 23. is\nch 4 is\nch 56 is\n'
re.compile(r'ch \d{1,}[.]').findall(text)
['ch 1.', 'ch 23.']
re.compile(r'ch \d{1,}[^.]').findall(text)
['ch 23', 'ch 4 ', 'ch 56 ']
I can guess why the 'ch 23' appears in the second list. But how to get
rid of it?
--Jach
>>> import re
>>> text = 'ch 1. is\nch 23. is\nch 4 is\nch 56 is\n'
>>> re.findall(r'ch \d+\.', text)
['ch 1.', 'ch 23.']
>>> re.findall(r'ch \d+(?!\.)', text) # (?!\.) for negated look ahead
['ch 2', 'ch 4', 'ch 56']
import regex
# regex is more powerful that re
>>> text = 'ch 1. is\nch 23. is\nch 4 is\nch 56 is\n'
>>> regex.findall(r'ch \d++(?!\.)', text)
['ch 4', 'ch 56']
## ++ means "possessive", no backtrack is allowed
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