David Raymond <david.raym...@tomtom.com> writes: >> def how_many_times(): >> x, y = 0, 1 >> c = 0 >> while x != y: >> c = c + 1 >> x, y = roll() >> return c, (x, y) > > Since I haven't seen it used in answers yet, here's another option using our > new walrus operator > > def how_many_times(): > roll_count = 1 > while (rolls := roll())[0] != rolls[1]: > roll_count += 1 > return (roll_count, rolls)
That's nice, although it doesn't seem more readable to a novice seeing a while for the first time, seeing a loop for the first time, than that while-True version. In fact, I think the while-True is the clearest so far. But it's always nice to spot a walrus in the wild! (If you're somewhere safe, that is.) -- https://mail.python.org/mailman/listinfo/python-list
