Am 20.11.21 um 20:15 schrieb Ulli Horlacher:
Stefan Ram <r...@zedat.fu-berlin.de> wrote:
r...@zedat.fu-berlin.de (Stefan Ram) writes:
except Exception as inst:
print( traceback.format_exc() )
More to the point of getting the line number:
As I wrote in my initial posting:
I already have the line number. I am looking for the source code line!
So far I use:
m = re.search(r'\n\s*(.+)\n.*\n$',traceback.format_exc())
if m: print('%s %s' % (prefix,m.group(1)))
Stefan Ram's solution missed only the line content. Here it is.
import sys
import traceback
try:
1/0
except ZeroDivisionError as exception:
tr = traceback.TracebackException.from_exception( exception )
x = tr.stack[0]
print("Exception %s in line %s: %s" % (exception, x.lineno, x.line))
The traceback object does not only contain the lineno but also the
content of the offending line.
--------------
Paolo
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