Am 07.06.22 um 23:01 schrieb Christian Gollwitzer:
In [3]: re.sub(r'^\d+\s*', '', s) Out[3]: 'Trinket'
that RE does match what you intended to do, but not exactly what you wrote in the OP. that would be '^\d\d.' start with exactly two digits followed by any character.
Christian
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