Paul Rubin calculates exp(1000.0): > You could rearrange your formulas to not need such big numbers: > > x = 1000. > log10_z = x / math.log(10) > c,m = divmod(log10_z, 1.) > print 'z = %.5fE%d' % (10.**c, m)
Nice approach. We should never forget that we do have mathematical skills beside the computers. But, shouldn't you switch c and m in the last row? /MiO -- http://mail.python.org/mailman/listinfo/python-list
