jak <nos...@please.ty> writes:
Alan Bawden ha scritto:
> Julieta Shem <js...@yaxenu.org> writes:
>
> How would you write this procedure?
> def powers_of_2_in(n):
> ...
>
> def powers_of_2_in(n):
> return (n ^ (n - 1)).bit_count() - 1
>
Great solution, unfortunately the return value is not a tuple as in the
OP version. Maybe in this way?
def powers_of_2_inB(n):
bc = (n ^ (n - 1)).bit_count() - 1
return bc, int(n / (1 << bc))
Good point. I overlooked that. I should have written:
def powers_of_2_in(n):
bc = (n ^ (n - 1)).bit_count() - 1
return bc, n >> bc
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