Matt, other mail is more relevant - seems to maybe have more to do with
different behavour if import code, or not - no, does not make sense to
me - but, here's the command line contents including printing out id()
results, but, only working via importing code:
#---start session---
C:\temp\py_try>type scoping2.py
from datetime import datetime, timezone, timedelta
dt_expiry = datetime.strptime("1970-01-01 00:00", "%Y-%m-%d
%H:%M").replace(tzinfo=timezone.utc)
def do_it():
global dt_expiry
dt_expiry = datetime.now()+timedelta(minutes=5)
print("date value", dt_expiry.strftime("%Y-%m-%d %H:%M"))
print("ID", id(dt_expiry))
# end of do_it function
C:\temp\py_try>python
Python 3.11.7 (tags/v3.11.7:fa7a6f2, Dec 4 2023, 19:24:49) [MSC v.1937
64 bit (AMD64)] on win32
Type "help", "copyright", "credits" or "license" for more information.
>>> from scoping2 import *
>>> print(dt_expiry)
1970-01-01 00:00:00+00:00
>>> print(id(dt_expiry))
1808577867152
>>> do_it()
date value 2024-03-06 18:39
ID 1808572660736
>>> print(dt_expiry)
1970-01-01 00:00:00+00:00
>>> print(id(dt_expiry))
1808577867152
>>>
---end session---
As in, the two different ID values are being returned outside and inside
the function, whereas, if I included that bit inside the interpreter
while typing code manually, chances are the same ID would be retained
both inside and outside function.
Jacob Kruger
+2782 413 4791
"Resistance is futile!...Acceptance is versatile..."
On 2024/03/06 15:57, Mats Wichmann via Python-list wrote:
On 3/6/24 05:55, Jacob Kruger via Python-list wrote:
Ok, simpler version - all the code in a simpler test file, and
working with two separate variables to explain exactly what am
talking about:
If you import the contents of that file into the python interpreter,
dt_expiry will start off as "1970-01-01 00:00", and, if you execute
do_it function, it will print out the new value assigned to the
dt_expiry variable inside that function, but if you then again check
the value of the dt_expiry variable afterwards, it's reverted to the
1970... value?
If I take out the line that removes values from l_test #
l_test.clear() # before appending new value to it, then it will also
not retain it's new/additional child items after the function exits,
and will just revert back to [1, 2, 3] each and every time.
In other words, with some of the variable/object types, if you use a
function that manipulates the contents of a variable, before then
re-assigning it a new value, it seems like it might then actually
update/manipulate the global variable, but, either just calling
purely content retrieval functions against said objects, or assigning
them new values from scratch seems to then ignore the global scope
specified in the first line inside the function?
Hope this makes more sense
No, it doesn't. Your code is working as one would expect. For example,
adding prints for the l_test variable, and removing the .clear() which
you claim makes it not work, shows me:
before: l_test=[1, 2, 3], id(l_test)=140153285385856
leaving do_it: l_test=[1, 2, 3, 1, 2, 3, 99], id(l_test)=140153285385856
after: l_test=[1, 2, 3, 1, 2, 3, 99], id(l_test)=140153285385856
It's the same list object, as you can see by the id values. And the
list is updating as expected.
And... you don't need the global statement for l_test. As it's
mutable, you can mutate it in the function; the global only acts on
assignment. Using "global" for that may make your intent more clear to
readers though, although static checkers will grumble at you.
You must be doing something additional that you're not telling us about.
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