Antoon, Even if the suggested solution offers a partial result, you would need specific requirements to determine what should be done if one or more of the parts being cycled is shorter than the others. Stopping at that point is one option. Another is to continue but only interleave ones still producing and in the same order.
There is a function in itertools called zip_longest() that might be considered as it keeps going but substitutes a customizable value for "missing" parts. You could then, perhaps, make a change so that sentinel is not passed along. -----Original Message----- From: Python-list <python-list-bounces+avi.e.gross=gmail....@python.org> On Behalf Of Antoon Pardon via Python-list Sent: Wednesday, April 3, 2024 5:11 AM To: python-list@python.org Subject: Re: A missing iterator on itertools module? Op 28/03/2024 om 17:45 schreef ast via Python-list: > Hello > > Suppose I have these 3 strings: > > s1 = "AZERTY" > s2 = "QSDFGH" > s3 = "WXCVBN" > > and I need an itertor who delivers > > A Q W Z S C E D C ... > > I didn't found anything in itertools to do the job. The documentation mentions a roundrobin recipe. > > So I came up with this solution: > > > list(chain.from_iterable(zip("AZERTY", "QSDFGH", "WXCVBN"))) > > ['A', 'Q', 'W', 'Z', 'S', 'X', 'E', 'D', 'C', 'R', 'F', 'V', 'T', 'G', > 'B', 'Y', 'H', 'N'] But if your strings are not equal, this will only produce a partial result. -- https://mail.python.org/mailman/listinfo/python-list -- https://mail.python.org/mailman/listinfo/python-list