[EMAIL PROTECTED] wrote: > Apparently, calling bind() with a zero "port" will choose some available port > number, as demonstrated by this program: > > import socket > s = socket.socket(socket.AF_INET, socket.SOCK_STREAM) > s.bind(("", 0)) > print s.getsockname() > > Here's how it behaved over several runs: > $ python soc.py > ('0.0.0.0', 34205) > $ python soc.py > ('0.0.0.0', 34206) > $ python soc.py > ('0.0.0.0', 34207) > > I don't know for sure whether this is standard behavior for sockets, or > whether > it's a special behavior of linux. > It's been standard behaviour ever since the Berkeley socket interface was defined, as far as I know.
regards Steve -- Steve Holden +44 150 684 7255 +1 800 494 3119 Holden Web LLC www.holdenweb.com PyCon TX 2006 www.python.org/pycon/ -- http://mail.python.org/mailman/listinfo/python-list