Flavio wrote:
> Hi,
>
> I heard time and again that you are not _supposed_ to update the
> locals dictionary.
>
> Can anyone tell me why, if the following code works, I should not do
> this?
>
> #
> # Extending Local namespace
> #
>
> def fun(a=1,b=2,**args):
>
> print 'locals:',locals()
> locals().update(args)
> print locals()
>
> e = {'s':3,'e':4}
> fun(k=10,v=32,**e)
>
Because it depends on the current implementation and isn't guaranteeed
to work in the future.
regards
Steve
--
Steve Holden +44 150 684 7255 +1 800 494 3119
Holden Web LLC www.holdenweb.com
PyCon TX 2006 www.python.org/pycon/
--
http://mail.python.org/mailman/listinfo/python-list
