I want to scan a file byte for byte for occurences of the the four byte pattern 0x00000100. I've tried with this:
# start import sys numChars = 0 startCode = 0 count = 0 inputFile = sys.stdin while True: ch = inputFile.read(1) numChars += 1 if len(ch) < 1: break startCode = ((startCode << 8) & 0xffffffff) | (ord(ch)) if numChars < 4: continue if startCode == 0x00000100: count = count + 1 print count # end But it is very slow. What is the fastest way to do this? Using some native call? Using a buffer? Using whatever? /David -- http://mail.python.org/mailman/listinfo/python-list