[EMAIL PROTECTED] wrote: > Hi. Thanks for the tip. However, implementing that example, the script > will only generate the second output "file", (or it's overwriting the > first one), so all I get when run is "fileb".
I think your looping code has the structure for x in ["a", "b", "c"]: pass print x This will print x once after the loop has completed. By then the value of x is "c". To fix it, move the code from /after/ the loop /into/ the loop: for x in ["a", "b", "c"]: print x In the code you give that would mean that you have to indent the try: # ... except: # ... statement one more level. Inside that loop you want a filename and an integer value in lockstep. The simplest way to get that is zip(): >>> for Disc, suffix in zip(xrange(2, 6, 2), "abcdefghijklmnopqrstuvwxyz"): ... Out_Dem = "out" + suffix ... print Disc, Out_Dem ... 2 outa 4 outb Again, you have to replace the print statement by your try...except. If you fear that you will eventually run out of suffices, here is a function that "never" does: >>> def gen_suffix(chars): ... for c in chars: ... yield c ... for c in gen_suffix(chars): ... for d in chars: ... yield c + d ... >>> for i, s in zip(range(20), gen_suffix("abc")): ... print i, s ... 0 a 1 b 2 c 3 aa 4 ab 5 ac 6 ba 7 bb 8 bc 9 ca 10 cb 11 cc 12 aaa 13 aab 14 aac 15 aba 16 abb 17 abc 18 aca 19 acb That said, reading the tutorial or an introductory book on Python never hurts... Peter -- http://mail.python.org/mailman/listinfo/python-list