Daniel Schüle wrote: > D H wrote: > > [EMAIL PROTECTED] wrote: > > > >>> You can use i**=2 for i in range(1000) instead > >> > >> > >> > >> I don't think one can use assignment in list comprehension or generator > >> expression. The limitation is very much like lambda. > >> > > > > i**2 > > lst=[i**2 for i in range(1000)] > > you will get a list with 1000 items > [0,1,4,9 ... ] > > is not the same as > > i,lst=2,[] > while i<1000: > i**=2 > lst.append(i) > > here you get [4,16,256,65536] > only 4 items > You want a combination of takewhile and scanl and filter. For this particular snippet, I think a simple loop is cleaner. I am bias towards one-liner but for this case, explicit loop beats it. Just define a short function.
-- http://mail.python.org/mailman/listinfo/python-list
