""" Ok, i am now understanding some of parseing and how to use it and nodes, things like that. But say i wanted to take the title of http://www.digg.com/rss/index.xml
and XMLTramp seemed the most simple to understand. would the path be something like this? import xmltramp rssDigg = xmltramp.load("http://www.digg.com/rss/index.xml") print note.rss.channel.item.title I think thats wat im having the most confusion on now, is how to direct to the path that i want... """ I suggest you read at least the front page information for the tools you are using. It's quite clear from the xmltramp Web site ( http://www.aaronsw.com/2002/xmltramp/ ) that you want tomething like (untested: the least homework you can do is to refine the example yourself): print rssDigg[rss.channel][item][title] BTW, in Amara, the API is pretty much exactly what you guessed: >>> import amara >>> rssDigg = amara.parse("http://www.digg.com/rss/index.xml") >>> print rssDigg.rss.channel.item.title Video: Conan O'Brien iPod Ad Parody -- Uche Ogbuji Fourthought, Inc. http://uche.ogbuji.net http://fourthought.com http://copia.ogbuji.net http://4Suite.org Articles: http://uche.ogbuji.net/tech/publications/ -- http://mail.python.org/mailman/listinfo/python-list