On Wed, 21 Dec 2005 03:37:27 -0800, Neuruss wrote:
> Can't we just check if the string has digits?
Why would you want to?
> For example:
>
>>>> x = '15'
>>>> if x.isdigit():
> print int(x)*3
15 is not a digit. 1 is a digit. 5 is a digit. Putting them together to
make 15 is not a digit.
If you really wanted to waste CPU cycles, you could do this:
s = "1579"
for c in s:
if not c.isdigit():
print "Not an integer string"
break
else:
# if we get here, we didn't break
print "Integer %d" % int(s)
but notice that this is wasteful: first you walk the string, checking each
character, and then the int() function has to walk the string again,
checking each character for the second time.
It is also buggy: try s = "-1579" and it will wrongly claim that s is not
an integer when it is. So now you have to waste more time, and more CPU
cycles, writing a more complicated function to check if the string can be
converted.
--
Steven.
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