Hi Tim,
Thanks a lot! That sounds like quite a
useful routine, that I can use without going through extra documentation and
adding extra libraries!
Cheers,
--Tim J
From: Tim Williams
(gmail) [mailto:[EMAIL PROTECTED]
Sent: donderdag 22 december 2005
16:38
To: Leeuw van der, Tim
Cc: python-list@python.org
Subject: Re: Parsing a date-time
string?
On 21 Dec 2005 01:43:13 -0800, Tim N. van der Leeuw <[EMAIL PROTECTED]>
wrote:
Hi,
I want to parse strings containing date-time, which look like the
following:
"Mon Dec 19 11:06:12:333 CET 2005"
[snipped]
What I want to get is some sort of sortable date; either as a number or
(if nothing else) as a string in ISO8601 format.
Its slow in the office today, so: ......
######
from email import Utils
import time
zones = {'CET': '+0100', 'GMT': '0000', 'EST': '-0500', 'PST': '-0800'}
def get_sortable_time(a_date):
split_date = a_date.split()
split_time =
split_date[3].split(':')
# split the time
microsecs = float('0.'+ split_time[-1]) # get
the microseconds
split_date[3] = ':'.join(split_time[:-1])
# join time, without microseconds
split_date[4] = zones[split_date[4]] # convert
the timezone to '-0800' format
split_date = ' '.join(split_date)
# eg "Mon Dec 19 11:06:12 +0100 2005"
gmt_time_as_num =
Utils.mktime_tz(Utils.parsedate_tz(split_date) ) # eg 1134993972.0
return gmt_time_as_num + microsecs #
time in GMT, eg 1134993972.33
sortable_time = get_sortable_time( "Mon Dec 19 11:06:12:333 CET 2005"
)
print sortable_time # = 1134993972.33
(in time.time() format )
print
time.ctime(sortable_time)
# Mon Dec 19 12:06:12 2005
######
You could remove the 2 "microsecs" references if you don't need that
level of granularity
HTH :)
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