> Alternately, the need can be met with existing tools by pre-padding the
> iterator with enough extra values to fill any holes:
>
> it = chain(iterable, repeat('', group_size-1))
> result = izip_longest(*[it]*group_size)Typo: That should be izip() instead of izip_longest() -- http://mail.python.org/mailman/listinfo/python-list
