Since I want to just launch the new process, naturally I looked at os.execl(). However, I can't figure out how to make it work:
>>> import os
>>> os.execl("c:\\spreadsheet.xls")
Traceback (most recent call last):
File "<input>", line 1, in ?
File "C:\Python24\lib\os.py", line 309, in execl
execv(file, args)
OSError: [Errno 8] Exec format error
>>> os.execl("c:\\spreadsheet.xls", "c:\\spreadsheet.xls")
Traceback (most recent call last):
File "<input>", line 1, in ?
File "C:\Python24\lib\os.py", line 309, in execl
execv(file, args)
OSError: [Errno 8] Exec format error
Is there some trick? I _think_ I'm doing what the docs desribe...
I've tried to Google around and I can't find anything of use. Having said that, I'd really appreciate it if someone could give me the right 2 word Google search that pops up exactly what I'm looking for. ;->
Thanks!
Chris
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