Fredrik Lundh wrote:
> Giovanni Bajo wrote:
>
> > ------- foo.py -----
> > def iters(n):
> > s = ''
> > for i in xrange(n):
> > s += chr(i%64)
> > return s
> >
> > def iters2(n):
> > L = []
> > for i in xrange(n):
> > L.append(chr(i%64))
> > return "".join(L)
> > ------- foo.py -----
> >
> > So, look, it's even faster than the solution you're proposing.
>
> since you know the length, you can preallocate the list
>
> def iters3(n):
> L = [None]*n
> for i in xrange(n):
> L[i] = chr(i%64)
> return "".join(L)
>
> or use a preallocated array
>
> def iters4(n):
> L = array.array("B", [0])*n
> for i in xrange(n):
> L[i] = i%64
> return L.tostring()
>
> on my machine, the last one is twice as fast as your "even faster"
> solution under 2.4. in earlier versions, it's just under 5 times faster.
>
> for the OP's problem, a PIL-based solution would probably be ~100
> times faster than the array solution, but that's another story.
>
What do you mean by a PIL based solution? The reason I need to get the
data into the string list is so I can pump it into PIL to give me my
image... If PIL has a way to make it easier, I do not know it, but
would like to know it.
> </F>
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