On 2/17/06, Brian Blais <[EMAIL PROTECTED]> wrote:
This was the line causing the type error. t is type double (float64). 'f' makes x be type float32. That causes the assignment below to fail. Replacing that line with
x=zeros(len(t),'d')
should work. Or the zeros_like() that Travis suggested.
You could also use
idx=where(t>5)
In place of
idx=(t>5)
Although in this case it probably doesn't make much difference, where(expr) is more directly equivalent to matlab's find(expr).
See http://www.scipy.org/Wiki/NumPy_for_Matlab_Users for more Matlab equivalents. And consider contributing your own, if you have some good ones that aren't there already.
--bb
Colin J. Williams wrote:
> Brian Blais wrote:
>> In my attempt to learn python, migrating from matlab, I have the
>> following problem. Here is what I want to do, (with the wrong syntax):
>>
>> from numpy import *
>>
>> t=arange(0,20,.1)
>> x=zeros(len(t),'f')
This was the line causing the type error. t is type double (float64). 'f' makes x be type float32. That causes the assignment below to fail. Replacing that line with
x=zeros(len(t),'d')
should work. Or the zeros_like() that Travis suggested.
>>
>> idx=(t>5) # <---this produces a Boolean array, probably not what you want.
>> tau=5
>> x[idx]=exp(-t[idx]/tau) # <---this line is wrong (gives a TypeError)
>>
You could also use
idx=where(t>5)
In place of
idx=(t>5)
Although in this case it probably doesn't make much difference, where(expr) is more directly equivalent to matlab's find(expr).
See http://www.scipy.org/Wiki/NumPy_for_Matlab_Users for more Matlab equivalents. And consider contributing your own, if you have some good ones that aren't there already.
--bb
-- http://mail.python.org/mailman/listinfo/python-list
