"Tuvas" <[EMAIL PROTECTED]> writes:
> Wait, I now see that there is a native base 2 log in python, so I will
> just do that rather than my adhoc way. The reason for adding one is to
> make sure there isn't any problems if the log is, for instance, 2.2. It
> will always round up. It's better to have to try twice to make sure the
> number can have the max range than never use the top half, as the first
> version did... That changes the function to:
OK, if the log is one too high, you just have to do a few additional
retries.
> As to the s2num(text), well, that looks really neat. Is there an easy
> way to do the reverse of that? Thanks!
from binascii import unhexlify
def num2s(n):
s = '%X' % n
if len(s) % 2 == 1:
s = '0' + s # make sure length of hex string is even
return unhexlify(s)
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