Max M wrote:
> decorated = [(obj.x, obj) for obj in objects]
> max_decorated = max(decorated)
> max_obj = max_decorated[-1]
Python 2.5 will make this even easier - max() and min() aquire a `key`
keyword parameter much like list.sort()/sorted().
max_obj = max(objects, key=operator.attrgetter('x'))
Also, using your DSU version, you should (nearly) always include the
object index in the tuple so you don't break ties by comparing the
actual objects i.e.
decorated = [(obj.x, i, obj) for (i, obj) in enumerate(objects)]
max_decorated = max(decorated)
max_obj = max_decorated[-1]
Note that this will always return the *last* entry with maximum obj.x as
the max - to return the first one found, use (obj.x, -i, obj).
Tim Delaney
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