Steven D'Aprano wrote: > On Wed, 05 Apr 2006 16:21:02 +0200, Georg Brandl wrote: > >> Because of backwards compatibility. range() returns a list, xrange() an >> iterator: list(xrange(...)) will give the same results as range(...). > > Georg is pretty much correct in his explanation, but just to dot all the > I's and cross all the T's, we should explain that xrange() doesn't return > an iterator, it returns a special xrange object:
Ah yes, the old iterator <-> iterable problem ;) Georg -- http://mail.python.org/mailman/listinfo/python-list
