In my program I have a lot of statements that append elements, but
sometimes I don't want to append the element so it requres an if
statement to check it, and that requires assigning the returned element
from a function to a name or calling the funtion twice.
e = ET.Element('name')
e.append(get_subelement(obj)) # but raises an exception on None
This works, but I have a lot of appends.
sube = get_element(obj)
if sube is None:
e.append(sube)
Now if Elements worked more like lists I could extend an element.
alist = []
alist.extend([]) # returns orginal list
With strings.
s = ''
s += '' # returns original string (or copy)
So is there an identity operation with Element Tree elements that I can
use to avoid putting a lot of if and or try statements around appending
elements?
I could wrap the append and do it this way...
def eappend(e1, e2):
if e2 is None: return e1
e1.append(e2)
return e1
Then do...
e = eappend(e, get_element(obj)) # Append if not None.
But maybe there's a better way?
Ron
--
http://mail.python.org/mailman/listinfo/python-list
