Thanks. Do you know of a solution to this? I tried the following, which I found on this newsgroup:
#============ lines = open(sys.argv[1]).readlines() #============ sys.stdin = open('/dev/tty') a = raw_input('Prompt: ') #============ sys.stdin = os.fdopen(3) a = raw_input('Prompt: ') #============ What I want to do is execute a scheduled task that prompts me for something and allows me to enter it and have it stored somewhere. I'm on Ubuntu Linux. Thanks in advance! Steven D'Aprano wrote: > On Sat, 08 Apr 2006 23:07:54 -0700, Rex Eastbourne wrote: > > > Hi, > > > > I'm executing a python script as a cron job. When I run it myself from > > the command line it works, but when cron executes it I get an EOFError: > > > > File "/home/rex/cronscript.py", line 6, in ? > > level = int(raw_input("hello?")) > > EOFError: EOF when reading a line > > > Because raw_input is waiting for input from the user. I assume that when > cron runs a Python script, and there is no actual human user to enter a > string in response to raw_input, it raises a EOF error. > > Written in the docs: > > http://docs.python.org/lib/module-exceptions.html > > > exception EOFError > Raised when one of the built-in functions (input() or raw_input()) > hits an end-of-file condition (EOF) without reading any data. (N.B.: > the read() and readline() methods of file objects return an empty > string when they hit EOF.) > > > -- > Steven. -- http://mail.python.org/mailman/listinfo/python-list